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X^2+10X-1500=0
a = 1; b = 10; c = -1500;
Δ = b2-4ac
Δ = 102-4·1·(-1500)
Δ = 6100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6100}=\sqrt{100*61}=\sqrt{100}*\sqrt{61}=10\sqrt{61}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{61}}{2*1}=\frac{-10-10\sqrt{61}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{61}}{2*1}=\frac{-10+10\sqrt{61}}{2} $
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